Practicing Success
Consider the following reaction: Name of the reaction is : |
Balz-Schiemann reaction Wurtz reaction Wurtz-Fittig reaction Fittig reaction |
Fittig reaction |
The correct answer is option 4. Fittig reaction. Fittig Reaction is a form of ‘Coupling Reaction’ in which two aryl(aromatic) groups combine in the presence of Sodium in dry ether or THF(Tetrahydrofuran) to form a biaryl species. Example: Halobenzene reacts in the presence of sodium metal in dry ether to form biphenyl. Here, \(X = Cl, Br, I\). Mechanism: There are mainly two experimentally proven reaction pathways of the Fittig Reaction: (i) Free Radical Mechanism (ii) The Organo-Alkali Mechanism (i) The Free Radical Mechanism The free radical mechanism involves the formation of free phenyl radicals, which are highly reactive. Step 1: Formation of Phenyl Free Radical In the presence of Sodium in dry ether, homolysis of the C-X bond of the Aryl Halide happens. This leads to the formation of a phenyl-free radical and NaX salt. Step 2: Coupling of the Benzene Rings The phenyl radicals formed in the previous step are highly reactive. Two phenyl radicals combine to form biphenyl (phenylbenzene or diphenyl). The Organo-Alkali Mechanism Another proven pathway to undergo this reaction is through the formation of an “Organo-Alkali” intermediate. Organic compounds form bonds with Alkali metals to form Organo-Alkali compounds. Step 1: Formation of the Organo-Alkali Intermediate Homolysis of the \(C-Cl\) bond in the Aryl Halide leads to the formation of phenyl radical, which combines with the sodium atom to form the Aryl-Sodium. Step 2: Nucleophilic Attack of the Organo-Alkali to the Aryl Halide Organo-Alkali is highly reactive in nature. The Aryl-Sodium here acts as a strong nucleophile and attacks the Aryl Halide present in the reaction mixture. This leads to the heterolysis of \(C-Na\) and \(C-Cl\) bonds. \(Na^+\) and \(Cl^–\) combine to form a salt. Phenyl-benzene is formed as the product of this nucleophilic addition. |