From a point P on a level ground, the angle of elevation of the top of the tower is 30o. If the distance of point P from the foot of the tower is 510m, then 50% of the height of the tower (in m) is :

85 $\frac{85\sqrt{3}}{3}$ $85\sqrt{3}$ $150 \sqrt{3}$

$85\sqrt{3}$

⇒ tan \({30}^\circ\) = \(\frac{QR}{510}\) ⇒ \(\frac{1}{√3}\) = \(\frac{QR}{510}\) ⇒ \(\frac{510}{√3}\) = QR 50% of QR = \(\frac{510}{√3 × 2}\) ⇒ 85√3 m.