From a point P on a level ground, the angle of elevation of the top of the tower is 30o. If the distance of point P from the foot of the tower is 510m, then 50% of the height of the tower (in m) is :
Answer & explanation
Correct answer: option 3
⇒ tan \({30}^\circ\) = \(\frac{QR}{510}\)
⇒ \(\frac{1}{√3}\) = \(\frac{QR}{510}\)
⇒ \(\frac{510}{√3}\) = QR
50% of QR = \(\frac{510}{√3 × 2}\)
⇒ 85√3 m.