Practicing Success
Two persons P and Q can do a job together in 36 days. P is 3 times as efficient as Q. In how many days can Q alone complete the work? |
148 140 144 146 |
144 |
P + Q = 36 days, Given, P is 3 times more efficient than Q, i.e; P : Q Efficiency 3 : 1 now, (3 + 1) x 36 = 144 units ..(Total Efficiency × Days = Total work) ⇒ time taken bv Q to complete the whole work by himself = \(\frac{work}{efficincy}\) = \(\frac{144}{1}\) = 144 days.
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