In a p type semiconductor the acceptor level is situated 50 meV above the valence band. The maximum wavelength of light required to produce a hole will be:

$2.48 × 10^{-5} m$

The correct answer is Option (3) → $2.48 × 10^{-5} m$

Energy required to excite an electron from the valence bond, $E=50meV$

and,

the relationship between the energy E of light is,

$E=\frac{hc}{λ}=\frac{4.135×10^{-15}×3×10^8}{50×10^{-3}}$

$=2.48 × 10^{-5} m$