Practicing Success
The value(s) of \(p\) so that the lines \(\frac{1-x}{3}=\frac{7y-14}{2p}=\frac{z-3}{2}\) and \(\frac{7-7x}{3p}=\frac{y-5}{1}=\frac{6-z}{5}\) are at right angles |
\(\frac{7}{11}\) \(\frac{70}{11}\) \(\frac{11}{70}\) \(\frac{11}{7}\) |
\(\frac{70}{11}\) |
For right angles \(a_{1}a_{2}+b_{1}b_{2}+c_{1}c_{2}=0\) |