CUET Preparation Today
CUET
-- Applied Mathematics - Section B2
Algebra
If $-\frac{1}{3x-5}≤0$, then :
$x> \frac{5}{3}$
$x≥ \frac{5}{3}$
$x< \frac{5}{3}$
$x≤ \frac{5}{3}$
The correct answer is Option (1) → $x> \frac{5}{3}$
$-\frac{1}{3x-5}≤0$
$⇒3x-5>0$
$⇒3x>5$
$⇒x>\frac{5}{3}$
