If f : R → R defined by $f(x) =\frac{6x+3}{2}$ is an invertible function, then find ${ f }^{ -1 }$
Answer & explanation
Correct answer: option 1
$y=\frac{6x+3}{2}⇒2y=6x+3⇒2y-3=6x$
$⇒x=\frac{2y-3}{6}$ so $f^{-1}=\frac{2x-3}{6}$
If f : R → R defined by $f(x) =\frac{6x+3}{2}$ is an invertible function, then find ${ f }^{ -1 }$
Correct answer: option 1
$y=\frac{6x+3}{2}⇒2y=6x+3⇒2y-3=6x$
$⇒x=\frac{2y-3}{6}$ so $f^{-1}=\frac{2x-3}{6}$