If the length of diagonal AC of square ABCD is 5.2 cm, then its area is?

15.12 sq. cm 13.52 sq. cm 16.62 sq. cm 20.28 sq. cm

13.52 sq. cm

Diagonal of a square = \(\sqrt {2}\) × side ⇒ 5.2 = \(\sqrt {2}\) side ⇒ side = \(\frac{5.2}{\sqrt {2}}\)           = 2.6\(\sqrt {2}\) cm area = side2 = (2.6\(\sqrt {2}\))2 = 6.76 × 2 = 13.52 sq. cm