If the length of diagonal AC of square ABCD is 5.2 cm, then its area is?
Answer & explanation
Correct answer: option 2
Diagonal of a square = \(\sqrt {2}\) × side
⇒ 5.2 = \(\sqrt {2}\) side
⇒ side = \(\frac{5.2}{\sqrt {2}}\)
= 2.6\(\sqrt {2}\) cm
area = side2 = (2.6\(\sqrt {2}\))2 = 6.76 × 2 = 13.52 sq. cm