A \(0.5\,\mathrm{C}\) charge consists of how many electronic charges?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \(3.125\times10^{18}\)
Charge is quantised: any charge is a whole-number multiple of the electronic charge \( e = 1.6\times10^{-19}\,\mathrm{C} \). So the number of electronic charges is the total charge divided by e.
\( \displaystyle q = ne \)
\( \displaystyle n = \frac{q}{e} \)
\( \displaystyle n = \frac{0.5\,\mathrm{C}}{1.6\times10^{-19}\,\mathrm{C}} \)
\( \displaystyle n = 3.125\times10^{18} \)