Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $\frac{x}{2}-\frac{4\left(\frac{15}{2}-\frac{x}{3}\right)}{3}=-\frac{x}{18}$, then the value of x is:

Options:

-10

$\frac{9}{8}$

10

$-\frac{9}{8}$

Correct Answer:

10

Explanation:

$\frac{x}{2}-\frac{4\left(\frac{15}{2}-\frac{x}{3}\right)}{3}=-\frac{x}{18}$

\(\frac{x}{2}\) - \(\frac{ 4 ( 45 - 2x ) }{18}\) = -\(\frac{x}{18}\)

\(\frac{x}{2}\) - \(\frac{ 2 ( 45 - 2x ) }{9}\) = -\(\frac{x}{18}\)

 \(\frac{ 9x - 4 ( 45 - 2x ) }{18}\) = -\(\frac{x}{18}\)

9x - 180 + 8x = -x

18x = 180

x = 10

The correct answer is Option (3) → 10