Practicing Success
The ionisation energy of 10 times ionised sodium atom is |
13.6 eV 13.6 × 11 eV $\frac{13.6}{11} eV$ $13.6 \times(11)^2 eV$ |
$13.6 \times(11)^2 eV$ |
$\left(E_{\text {ion }}\right)_{N a}=Z^2\left(E_{\text {ion }}\right)_H=(11)^2 13.6 eV$ |