Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Applications of Derivatives

Question:

The minimum value of $f(x) = |3 –x| + |2 + x| + |5 –x|$ is

Options:

0

7

8

10

Correct Answer:

7

Explanation:

The function f is decreasing for x and increases on (3 , ).

Hence x = 3 is a point of minimum and min f (x) = 7.