Two slits are made 0.1 mm apart and the screen is placed 2 m away. The fringe separation when a light of wavelength 500 nm is used is __________.

Fill in the blank with the correct answer from the options given below.

1 cm

Fringe width $ \beta = \frac {\lambda D}{d} = \frac{500 nm\times  2}{0.1 mm} = 1 cm$

The correct answer is Option (1) → 1 cm