CUET Preparation Today
The area of the smaller part of the circle \(x^2+y^2=a^2\) cutoff by the line \(x=\frac{a}{\sqrt{2}}\) is |
\(\frac{a^2(\pi-2)}{4}\) \(\frac{a^2(\pi-2)}{3}\) \(\frac{a^2(\pi-3)}{4}\) \(\frac{a^2(\pi-4)}{4}\) |
\(\frac{a^2(\pi-2)}{4}\) |
