In a ΔABC, the internal bisectors of the angle B and the angle C intersect at an angle of 105°. What is the value of the angle A?

52.5° 75° 15° 30°

30°

In ∆ABC, if internal bisectors of angles B and C join at D, ⇒ BDC = 90 + BAC /2 Thus, 105 = 90 + A\2 A = 30°