$\underset{x→0}{\lim}x^x$ is:

0 1 -1 ∞

1

$y=\underset{x→0}{\lim}x^x⇒ln\,y=\underset{x→0}{\lim}x\,ln,x⇒\underset{x→0}{\lim}\frac{ln\,x}{1/x}=\underset{x→0}{\lim}\frac{1/x}{-1/x^2}⇒\log y=0⇒y=e^0=1$