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CUET
General Aptitude Test
Quantitative Reasoning
Algebra
If $x+\frac{1}{x}=1$, then the value of $x^{12}+x^9+x^6+x^3+1$ is:
1
-1
0
-2
If $x+\frac{1}{x}=1$
then , x3 = -1
$x^{12}+x^9+x^6+x^3+1$
= (x3)4 + (x3)3 + (x3)2 + x3 + 1
= (-1)4 + (-1)3 + (-1)2 - 1 + 1
= 1 - 1 + 1 - 1 + 1
= 1
