If $x+\frac{1}{x}=1$, then the value of $x^{12}+x^9+x^6+x^3+1$ is:

1 -1 0 -2

1

If $x+\frac{1}{x}=1$ then , x3 = -1 $x^{12}+x^9+x^6+x^3+1$ = (x3)4 + (x3)3 + (x3)2 + x3 + 1 = (-1)4 + (-1)3 + (-1)2 - 1 + 1 =  1 - 1 + 1 - 1 + 1 = 1