'a' is inversely proportional to the cube of 'b'. The value of 'b' is 2 when the value of 'a' is 3. Then find the value of 'b' when the value of 'a' is \(\frac{8}{9}\):
Answer & explanation
Correct answer: option 3
ATQ,
a = \(\frac{1}{b^3} K\)
3 = \(\frac{1}{2^3} K\)
3 = \(\frac{1}{8}\) K
K= 24
Now,
\(\frac{8}{9}\) = \(\frac{1}{b^3}\) K
b3 = \(\frac{9}{8}\) × 24
b3 = 9 × 3 = 27
b = 3