If sin x - cos x = 0, 0° < x <

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If sin x - cos x = 0, 0° < x < 90° then the value of (sec x + cosec x)² is :

Options:

Correct Answer:

Explanation:

sin x - cos x = 0

sin x = cos x

{ we know, sinA = cos B iff A + B = 90º }

So,

x + x = 90º

2x = 90º

x = 45º

Now,

(sec x + cosec x)²

= (sec45º + cosec 45º)²

= ( √2 + √2)²

= (2 √2 )²

= 8