Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2 ×1010 Hz and amplitude 48 Vm-1. The wavelength of the wave is:

Options:

24 ×10-10 m

1.5 ×10-2 m

4.16 ×108 m

3 ×108 m

Correct Answer:

1.5 ×10-2 m

Explanation:

∵ Speed, c = vλ

∴ wavelength, $\lambda=\frac{c}{v}=\frac{3 \times 10^8}{2 \times 10^{10}}=1.5 \times 10^{-2} m$