I had to catch a bus which was 225 m ahead of me. The bus also started at the same time. If the speed of the bus was 2.5 m/sec and my speed was 36 kmph, in how much time I can catch the bus?

30 seconds

Speed = \(\frac{ Distance}{ Time}\)

Speed of person - 36 km/hr 

Speed of person in m/s = 36 x \(\frac{5 }{18 }\) = 10 m/s

Speed of bus = 2.5 m/s

So, putting values in the formulae:

Speed = \(\frac{ Distance}{ Time}\)

10 - 2.5 = \(\frac{ 225}{ Time}\)

Time =  \(\frac{ 225}{7.5}\)

Time = 30 seconds