Find the number of electrons in 5 A of current flowing for 1 second.

125 x 1019  3.25 x 1019  3.125 x 1019  3.125 x 1020

3.125 x 1019

I = Ne/t I = 5 A ; t = 1 s ; e = 1.6 x 10-19 C N = tI/e = 3.125 x 1019