A current carrying rod of length 2 m is kept at an angle of 45 degrees with the magnetic field 0.5 T and carrying a current of 1.4 A. What will be the force experienced by the charge carriers?

1 N 0.5 N 1.414 N 2 N

1 N

F = IlB Sin θ I = 1.4 A ; l = 2 m ; B = 0.5 T ; θ = 45 F = 1.4x2x0.5x$\frac{1}{\sqrt 2} = 1N $