If cosec A = 10, then what is the value of 20 sin A + $9\sqrt{11}$ sec A ? Given that A is an acute angle ?

23 34 32 30

32

cosec  A =  \(\frac{10 }{1}\) { cosec A =  \(\frac{H}{P}\) } P² + B² = H² 1² + B² = 10² B = 3\(\sqrt {11 }\) Now, 20 sinA + 9\(\sqrt {11 }\) secA = 20 × \(\frac{P}{H}\)  + 9\(\sqrt {11 }\)× \(\frac{H}{B}\)  = 20 × \(\frac{1}{10}\)  + 9\(\sqrt {11 }\)× \(\frac{10}{3√11}\) = 2 + 30 = 32