CUET Preparation Today
In a beryllium atom, if a0 be the radius of the first orbit, then the radius of the second orbit will be in general |
$na_0$ $a_0$ $n^2 a_0$ $\frac{a_0}{n^2}$ |
$n^2 a_0$ |
$r \propto n^2 \quad \Rightarrow \quad r_n=n^2 a_0 \quad\left(∵ r_1=a_0\right)$ |
