If sec θ + tan θ = p ; (p > 1) ; then value of \(\frac{cosec θ + 1}{cosec θ - 1}\) is?
Answer & explanation
Correct answer: option 3
Put p = 3
sec θ + tan θ = 3
sec θ - tan θ = \(\frac{1}{3}\)
⇒ 2sec θ = \(\frac{10}{3}\) ⇒ sec θ = \(\frac{5}{3}\)
then cosec θ = \(\frac{5}{4}\)
\(\frac{cosec θ + 1}{cosec θ - 1}\) = \(\frac{\frac{5}{4} + 1}{\frac{5}{4} - 1}\) = 9 or p2