If $x + \frac{1}{x}= 4$, then find the value of $x^4 +\frac{1}{x^4}$.
Answer & explanation
Correct answer: option 2
If $K+\frac{1}{K}=n$
then, $K^2+\frac{1}{K^2}$ = n2 – 2
If $x + \frac{1}{x}= 4$,
then the value of $x^2 +\frac{1}{x^2}$ = 42 – 2 = 14
then value of $x^4 +\frac{1}{x^4}$ = 142 – 2 = 194