A can do a piece of work in 20 days. B is 30% more efficient than A, and C is 50% more efficient than B. A and C work together for 3 days and then C leaves. A and B together will complete the remaining work in?
Answer & explanation
Correct answer: option 3
A : B : C
100 : 130
130 : 195
100 : 130 : 195
(divided 10)
10 : 13 : 19.5
A
Total work = 10 × 20
= 200
Total work in 3 days by A + C → 3 (10+ 19.5)
= 88.5
remaining work = 200 - 88.5 = 111.5
Now A + B taken days complete work = \(\frac{111.5}{10 + 13}\)
= 4\(\frac{39}{46}\)