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Find the area (in square units) of a triangle whose vertices are A (2, 4), B (3, 5) and C (-1, 3). |
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(x1 ,y1) = (2, 4), (x2,y2) = (3, 5) (x3 ,y3)= (-1, 3) Area of the triangle = [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]/2 Substitute the values in the formula ⇒ [2(5 – 3) + (3)(3 – 4) + 3(4 - 5)]/2 ⇒ [8 - 3 -3]/2 = 1 sq. units |
