The coordination number and oxidation number of M in the compound [M(SO₄)(NH₃)₅] will be

6 and 2

To find the coordination number and oxidation number of the central metal ion (M) in the compound \([M(SO4)(NH3)5]\), we need to analyze the ligands and their charges.

The complex contains two types of ligands:
1. \(SO4^{2-}\) (sulfate ion): This ligand has a charge of -2.
2. \(NH3\) (ammonia): This ligand is neutral.

Let's assign \(x\) as the oxidation state of the central metal ion (M).

Now, the total charge on the complex must be balanced, so we can write the equation as follows:

\(x + 5(0) + (-2) = 0\)
or, \(x - 2 = 0\)
or, \(x = 2\)

The oxidation state of the central metal ion (M) is +2.

The coordination number is the number of ligands directly bonded to the central metal ion. In this complex, there are one \(SO4^{2-}\) ion and five \(NH3\) ligands bonded to the central metal ion. So, the coordination number is 6.

Therefore, the correct answer is (3) 6 and 2.