Practicing Success
If $x + \frac{1}{x} = 5, $ then the value of $\frac{3x}{2x^2+2-5x}$ will be ____________. |
$\frac{5}{2}$ $\frac{2}{5}$ $\frac{3}{5}$ $\frac{5}{3}$ |
$\frac{3}{5}$ |
If $x + \frac{1}{x} = 5,$ then the value of $\frac{3x}{2x^2+2-5x}$ If $x + \frac{1}{x} = 5,$ then, \(\frac{x^2 + 1}{x}\) = 5 $x^2 + 1$ = 5x $2x^2 + 2$ = 10x Put in the required equation, $\frac{3x}{2x^2+2-5x}$ = $\frac{3x}{10x-5x}$ = \(\frac{3}{5}\) |