Let △ABC and △ABD be on the same base AB and between the same parallels AB and CD.Then the relation between areas of △ABC and △ABD will be:
Answer & explanation
Correct answer: option 2
We know that ,
Area of triangle = \(\frac{1}{2}\) × Base × Height
△ABC and △ABD , both triangles are on same base i.e. AB
And point C and D both are on also on same line ( perpendicular distance between both the line is same )
⇒ Height is also same.
So, Area of △ABC = Area of △ABD