Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

The solution of \(\frac{dy}{dx}=1+x+y+xy\) is

Options:

\(x-y=K\left(1+xy\right)\)

\(\log\left(1+y\right)=x+\frac{x^2}{2}+k\)

\(\log\left(1+x\right)+y+\frac{y^2}{2}=K\)

none of these

Correct Answer:

\(\log\left(1+y\right)=x+\frac{x^2}{2}+k\)

Explanation:

Given equation is separable