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If $A = [a_{ij}]$ is a skew-symmetric matrix of order $n$, then |
$a_{ij} = \frac{1}{a_{ji}} \forall i, j$ $a_{ij} \neq 0 \forall i, j$ $a_{ij} = 0, \text{ where } i = j$ $a_{ij} \neq 0 \text{ where } i = j$ |
$a_{ij} = 0, \text{ where } i = j$ |
The correct answer is Option (3) → $a_{ij} = 0, \text{ where } i = j$ ## In a skew-symmetric matrix, the $(i, j)^{th}$ element is negative of the $(j, i)^{th}$ element and all the diagonal elements are 0 i.e., $a_{ii} = 0$ Hence, the $(i, i)^{th}$ element = 0. |
