From a circular sheet of paper of radius 14 cm, two circles of radius 3.5 cm each along with a rectangle of length 3 cm and breadth 1 cm are removed. The area of the remaining sheet is:

(Use $\pi=\frac{22}{7}$)

536 cm²

Area of remaining sheet = Area of circular sheet - ( Area of two circles + Area of rectangle )

= πR² - ( 2πr² + l × b )

= π14² - ( 2π(3.5)² + 3 × 1 )

= \(\frac{22}{7}\) × 14 × 14 - ( 2× \(\frac{22}{7}\) × 3.5 × 3.5 + 3 × 1 )

= 616 - ( 77 + 3 )

= 536

The correct answer is Option (1) → 536 cm²