From a circular sheet of paper of radius 14 cm, two circles of radius 3.5 cm each along with a rectangle of length 3 cm and breadth 1 cm are removed. The area of the remaining sheet is:
(Use \(\pi=\frac{22}{7}\))
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 536 cm2
The remaining area is the area of the whole sheet minus the areas of the pieces cut out.
Area of the sheet \(\displaystyle =\frac{22}{7}\times14\times14=616\,\mathrm{cm^{2}}\)
Area of one small circle \(\displaystyle =\frac{22}{7}\times3.5\times3.5=38.5\,\mathrm{cm^{2}}\), so two circles \(=77\,\mathrm{cm^{2}}\)
Area of the rectangle \(=3\times1=3\,\mathrm{cm^{2}}\)
Remaining area \(=616-77-3=536\,\mathrm{cm^{2}}\)