A and B can do a work in 12 days, B and C in 15 days and A, B and C together take 10 days. Find the number of days taken by B alone.
Answer & explanation
Correct answer: option 1
Adding the efficiencies,
(A + B) + (B + C) = 9
(A + B + C) + B = 9
6 + B = 9
B = 3
Time taken by B alone = \(\frac{Total \; Work}{Efficiency}\)
= \(\frac{60}{3}\) = 20 days