Practicing Success
Let $\vec a$ and $\vec b$ be two unit vectors. Statement-1: $|\vec a+\vec b|+|\vec a −\vec b|=|\vec a| + |\vec b|$ Statement-2: The greatest value $|\vec a+\vec b|+|\vec a −\vec b|$ is $2\sqrt{2}$ |
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1. Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for Statement-1. Statement-1 is True, Statement-2 is False. Statement-1 is False, Statement-2 is True. |
Statement-1 is False, Statement-2 is True. |
Clearly, statement-1 is not true. Let θ be the angle between unit vectors $\vec a$ and $\vec b$. Then, $\vec a.\vec b=\cos θ$ Now, $|\vec a+\vec b|^2$ $=|\vec a|^2+|\vec b|^2+2\vec a.\vec b=2+2\cos θ=4\cos^2\frac{θ}{2}$ and, $|\vec a-\vec b|^2=|\vec a|^2+|\vec b|^2-2\vec a.\vec b=2-2\cos θ=4\sin^2\frac{θ}{2}$ $⇒|\vec a+\vec b|=2\cos\frac{θ}{2},|\vec a-\vec b|=2\sin\frac{θ}{2}$ $⇒|\vec a+\vec b|+|\vec a-\vec b|=2(\cos\frac{θ}{2}+\sin\frac{θ}{2})≤2\sqrt{2}$ So, statement-2 is true. |