If \((a-2)^2+(b-3)^2+(c-11)^2=0\), then find the value of \(\sqrt{a+b+c+9}\).
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 5
A square is never negative, so a sum of squares can be zero only when every square is zero.
\(a-2=0\), \(b-3=0\), \(c-11=0\), so \(a=2\), \(b=3\), \(c=11\)
\(a+b+c+9=2+3+11+9=25\)
\(\sqrt{25}=5\)