If x^2+1/(x^2)=98, then the value of x+1/x is:

If $x^2+\frac{1}{x^2}=98$,

then the value of $x+\frac{1}{x}$

If x² + \(\frac{1}{x^2}\) = b

and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\)

Then,  $x+\frac{1}{x}$ = \(\sqrt {98 + 2}\) = 10