Practicing Success
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If $x^2+\frac{1}{x^2}=98$, then the value of $x+\frac{1}{x}$ is: |
10 8 7 9 |
10 |
If $x^2+\frac{1}{x^2}=98$, then the value of $x+\frac{1}{x}$ If x2 + \(\frac{1}{x^2}\) = b and x + \(\frac{1}{x}\) = \(\sqrt {b + 2}\) Then, $x+\frac{1}{x}$ = \(\sqrt {98 + 2}\) = 10 |
