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If sin(A + B)=\(\frac{\sqrt {3}}{2}\) and tan(A - B) =\(\frac{1}{\sqrt {3}}\) find the value of (3A + 5B). |
120° 135° 210° 270° |
210° |
A + B=\(\frac{\sqrt {3}}{2}\) = 60° ...(i) A - B =\(\frac{1}{\sqrt {3}}\) = 30° ...(ii) Adding eq. (i) and (ii) 2A = 90° A = 45° B = 15° Now, (3A + 5B) = 3×45 + 5×15 = 135+75 = 210°
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