If sin(A + B)=\(\frac{\sqrt {3}}{2}\) and tan(A - B) =\(\frac{1}{\sqrt {3}}\)
find the value of (3A + 5B).
Answer & explanation
Correct answer: option 3
A + B=\(\frac{\sqrt {3}}{2}\) = 60° ...(i)
A - B =\(\frac{1}{\sqrt {3}}\) = 30° ...(ii)
Adding eq. (i) and (ii)
2A = 90°
A = 45°
B = 15°
Now, (3A + 5B) = 3×45 + 5×15
= 135+75
= 210°