Practicing Success
If $\int \frac{1-x^7}{x\left(1+x^7\right)} d x=a \ln |x|+b \ln \left|x^7+1\right|+C$, then |
$a=1, b=\frac{2}{7}$ $a=-1, b=\frac{2}{7}$ $a=1, b=-\frac{2}{7}$ $a=-1, b=-\frac{2}{7}$ |
$a=1, b=-\frac{2}{7}$ |
We have, $\int \frac{1-x^7}{x\left(1+x^7\right)} d x=a \ln |x|+b \ln \left|x^7+1\right|+C$ Differentiating both sides w.r. to, $x$, we get $\frac{1-x^7}{x\left(1+x^7\right)}=\frac{a}{x}+7 b \frac{x^6}{x^7+1}$ $\Rightarrow 1-x^7=a\left(1+x^7\right)+7 b x^7 \Rightarrow a=1, b=-\frac{2}{7}$ |