If \(A\) and \(B\) are two events such that \(P(A)=\frac{1}{3},P(B)=\frac{1}{4}\) and \(P(A \cup B)=\frac{1}{2}\) then the value of \(P(A|\bar{B})\) is
Answer & explanation
Correct answer: option 3
\(P(A\cup B)=P(A)+P(B)-P(A \cap B)\). Find \(P(A \cap B)\) and then find required probability