The maximum value of $\sin x.\cos x$ is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{1}{2}$
Given expression:
\(\sin x \cdot \cos x\)
Using identity:
\[ \sin x \cos x = \frac{1}{2} \sin 2x \]
The maximum value of \(\sin 2x\) is 1, so:
\[ \max(\sin x \cos x) = \frac{1}{2} \times 1 = \frac{1}{2} \]