Practicing Success
Practicing Success
CUET Preparation Today
$0 . \overline{42} \times(0.1 \overline{6} \div 0 . \overline{7})$ is equal to: |
$0 . \overline{099}$ $0 . \overline{090}$ $0.0 \overline{9}$ $0 . \overline{09}$ |
$0 . \overline{09}$ |
$0 . \overline{42} \times(0.1 \overline{6} \div 0 . \overline{7})$ = \(\frac{42}{99}\) × \(\frac{15}{90}\) × \(\frac{9}{7}\) = \(\frac{9}{99}\) = $0 . \overline{09}$ |
