$0 . \overline{42} \times(0.1 \overline{6} \div 0 . \overline{7})$ is equal to:
Answer & explanation
Correct answer: option 4
$0 . \overline{42} \times(0.1 \overline{6} \div 0 . \overline{7})$
= \(\frac{42}{99}\) × \(\frac{15}{90}\) × \(\frac{9}{7}\)
= \(\frac{9}{99}\) = $0 . \overline{09}$