If $6\sqrt{6}p^3 + 2\sqrt{2} q^3 = (\sqrt{6} p + \sqrt{2}q)(Sp^2 +Mq^2 - Npq)$ , then Me positive value of $\sqrt{S^2+M^2+2N^2}$ is:
Answer & explanation
Correct answer: option 2
A detailed explanation for this question is coming soon.
If $6\sqrt{6}p^3 + 2\sqrt{2} q^3 = (\sqrt{6} p + \sqrt{2}q)(Sp^2 +Mq^2 - Npq)$ , then Me positive value of $\sqrt{S^2+M^2+2N^2}$ is:
Correct answer: option 2
A detailed explanation for this question is coming soon.