CUET Preparation Today
A fair coin is tossed 5 times. The probability for all the event that at least one tail turns up, is: |
$\frac{31}{32}$ $\frac{15}{16}$ $\frac{1}{32}$ $\frac{1}{16}$ |
$\frac{31}{32}$ |
The correct answer is Option (1) → $\frac{31}{32}$ Total outcomes = $2^5=32$ P (all heads) = $(\frac{1}{2})^5=\frac{1}{32}$ P (at least one tail) = 1 - P (all heads) $=1-\frac{1}{32}=\frac{31}{32}$ |
