A fair coin is tossed 5 times. The probability for all the event that at least one tail turns up, is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{31}{32}$
Total outcomes = $2^5=32$
P (all heads) = $(\frac{1}{2})^5=\frac{1}{32}$
P (at least one tail) = 1 - P (all heads)
$=1-\frac{1}{32}=\frac{31}{32}$