Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to the equation $I=I_0 \sin \omega t$, where $I_0=10 A$, and $\omega=100 \pi rad/s$. The maximum value of emf in the second coil is (in V):
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $5 \pi$
According to faraday law,
$ε=M\frac{dI}{dt}$
M = Mutual inductance = 0.005 H
$I(t)=I_0\sin(ωt)$ [given]
$I_0=10A$
$ω=100\pi\,rad/s$
$\frac{dI}{dt}=I_0ω\cos(ωt)$
$ε_{max}=M.I_0.ω$ [Max. Current occurs when $\cos/ωt=1$]
$ε_{max}=0.005×10×100\pi$
$=5\pi V$