The number of electrons constituting \(1.5\) Faradays charge are:

\(9.03 \times 10^{23}\)

The correct answer is option 1. \(9.03 \times 10^{23}\). 

Faraday's constant is the amount of electric charge carried by one mole of electrons. Numerically, \(F \approx 96500\) Coulombs per mole. This value represents the total charge of Avogadro's number (\(6.022 \times 10^{23}\)) of electrons.

The charge of a single electron is \(1.602 \times 10^{-19}\) Coulombs.

Since \(F\) represents the charge carried by one mole of electrons, the number of electrons that make up one Faraday can be found using Avogadro's number, which is \(6.022 \times 10^{23}\) electrons.

We know,

1 Faraday = \(6.022 \times 10^{23}\) electrons

For \(1.5\) Faradays,

\(\text{Number of electrons} = 1.5 \times 6.022 \times 10^{23} \)

\(\text{Number of electrons} = 9.033 \times 10^{23}\)

So, \(1.5\) Faradays corresponds to approximately \(9.03 \times 10^{23}\) electrons.

Conclusion

The number of electrons constituting \(1.5\) Faradays of charge is \(9.03 \times 10^{23}\), which matches option 1.