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The integrating factor of the differential equation $\frac{dy}{dx}(xlogx)+y=2logx$ is given by: |
log (log x) ex log x x |
log x |
$\frac{dy}{dx}+\frac{1}{x\,log\,x}y=\frac{2}{x}⇒I.F.=e^{\int\frac{1}{x\,log\,x}}=e^{\log(log\, x)}=log x$ |
