The integrating factor of the differential equation $\frac{dy}{dx}(xlogx)+y=2logx$ is given by:
Answer & explanation
Correct answer: option 3
$\frac{dy}{dx}+\frac{1}{x\,log\,x}y=\frac{2}{x}⇒I.F.=e^{\int\frac{1}{x\,log\,x}}=e^{\log(log\, x)}=log x$
The integrating factor of the differential equation $\frac{dy}{dx}(xlogx)+y=2logx$ is given by:
Correct answer: option 3
$\frac{dy}{dx}+\frac{1}{x\,log\,x}y=\frac{2}{x}⇒I.F.=e^{\int\frac{1}{x\,log\,x}}=e^{\log(log\, x)}=log x$