If $P(A) = \frac{7}{13}$, $P(B) = \frac{9}{13}$ and $P(A \cap B) = \frac{4}{13}$, evaluate $P(A|B)$.

$\frac{4}{9}$

The correct answer is Option (2) → $\frac{4}{9}$ ##

Given the values:

• $P(A) = \frac{7}{13}$
• $P(B) = \frac{9}{13}$
• $P(A \cap B) = \frac{4}{13}$

Substitute the known values into the formula:

We have $P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{4}{13}}{\frac{9}{13}} = \frac{4}{9}$